339x-4.9x^2=0

Solution for 339x-4.9x^2=0 equation:

339x-4.9x^2=0

a = -4.9; b = 339; c = 0;
Δ = b2-4ac
Δ = 3392-4·(-4.9)·0
Δ = 114921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{114921}=339$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(339)-339}{2*-4.9}=\frac{-678}{-9.8}
=69+1/5.4444444444446
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(339)+339}{2*-4.9}=\frac{0}{-9.8}
=0
$